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OpenStudy (anonymous):

Solve the equation: e^x+e^-x=3?

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OpenStudy (anonymous):

fun!

OpenStudy (anonymous):

god, x=Ln (3+_\[\sqrt{5}\]/2)

OpenStudy (anonymous):

god doesn't play dice.

OpenStudy (anonymous):

e^2x + 1 = 3e^x e^2x - 3e^x +1 =0 i thik no real solution

OpenStudy (anonymous):

vicky007, are you sure? how'd you get e^2x? I'm confused on what you did.

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OpenStudy (anonymous):

e^x +e^(-x) =3 e^2x +1=3 e^x -3e^x + e^2x +1 =0 make e^x =A so A^2-3A+1=0 A=(3+-\[\sqrt{s}\])2

OpenStudy (anonymous):

|dw:1314330756421:dw|

OpenStudy (anonymous):

so x =Ln( what I draw)

OpenStudy (anonymous):

yeaaaaaaaaeeee.

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