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Solve the equation: e^x+e^-x=3?
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fun!
god, x=Ln (3+_\[\sqrt{5}\]/2)
god doesn't play dice.
e^2x + 1 = 3e^x e^2x - 3e^x +1 =0 i thik no real solution
vicky007, are you sure? how'd you get e^2x? I'm confused on what you did.
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e^x +e^(-x) =3 e^2x +1=3 e^x -3e^x + e^2x +1 =0 make e^x =A so A^2-3A+1=0 A=(3+-\[\sqrt{s}\])2
|dw:1314330756421:dw|
so x =Ln( what I draw)
yeaaaaaaaaeeee.
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