Question

Solve the equation: e^x+e^-x=3?

Answer 1

fun!

Answer 2

god, x=Ln (3+_\[\sqrt{5}\]/2)

Answer 3

god doesn't play dice.

Answer 4

e^2x + 1 = 3e^x
e^2x - 3e^x +1 =0
i thik no real solution

Answer 5

vicky007, are you sure? how'd you get e^2x? I'm confused on what you did.

Answer 6

e^x +e^(-x) =3
e^2x +1=3 e^x
-3e^x + e^2x +1 =0
make e^x =A
so A^2-3A+1=0
A=(3+-\[\sqrt{s}\])2

Answer 7

so x =Ln( what I draw)

Answer 8

yeaaaaaaaaeeee.