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OpenStudy (anonymous):

Is 98 a perfect square? Explain.

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OpenStudy (anonymous):

nope since : \[sqrt{98}\] can also be written as \[sqrt{49*2}\] 49 is the perfect square of 7 and 2 is not a perfect square hence the square root of 98 is \[sqrt{49*2}\] or \[\sqrt{2}*7\]

OpenStudy (anonymous):

Thanks :)

OpenStudy (anonymous):

my pleasure

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