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OpenStudy (anonymous):

what is the simplified form of y2-y-12/y^2-9

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OpenStudy (anonymous):

\[\frac{ y2-y-12}{y^2-9} \]

OpenStudy (anonymous):

i think (y-4)/(y-3)

OpenStudy (anonymous):

since (y-4)(y+3)/(y+3)(y-3) and (y+3) cancel out

OpenStudy (anonymous):

\[{y^2-4y+3y-12}{(y+3)(y-3)}\] \[\frac{(y-4)(y+3)}{(y+3)(y-3)}\] (y-4)/(y-3)

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