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OpenStudy (anonymous):

At what point is the tangent to f(x) = x^2 + 4x - 1 horizontal?

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OpenStudy (anonymous):

take the derivative, set it equal to zero, and solve. or else just find the vertex

OpenStudy (anonymous):

vertex is \[-\frac{b}{2a}=-\frac{4}{2}=-2\] so the point is \[(-2,-5)\]

OpenStudy (lalaly):

The tangent line will be horizontal at the vertex. You can either graph the equation to find it or you can complete the square.

OpenStudy (lalaly):

oh didnt see ur answer satellite,

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