Question

At what point is the tangent to f(x) = x^2 + 4x - 1 horizontal?

Answer 1

take the derivative, set it equal to zero, and solve. or else just find the vertex

Answer 2

vertex is
\[-\frac{b}{2a}=-\frac{4}{2}=-2\] so the point is
\[(-2,-5)\]

Answer 3

The tangent line will be horizontal at the vertex. You can either graph the equation to find it or you can complete the square.

Answer 4

oh didnt see ur answer satellite,