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Simplify the expression involving exponents as much as possible. No negative exponents, please! x ^-5 times (x^3)^4
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\[x^{-5}x^{3*4}=x^{12-5}=x^{7}\]
\[\large (x^{-5})(x^3)^4\] \[\large (x^{-5})(x^{3*4})\] \[\large (x^{-5})(x^{12})\] \[\large x^{-5+12}\] \[\large x^{7}\] So \[\large (x^{-5})(x^3)^4=x^7\]
what about a^3/a^6 times a^3/a.... would you treat it like a regular fraction?
ok thx
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