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12<(5/9)F-32
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\[12<\frac{5}{9}F-32 \le 32\] add 32 to all sides \[12+32<\frac{5}{9}F-32+32 \le 32+32\] \[44<\frac{5}{9}F \le 64\] multiply 9/5 on all sides \[\frac{9}{5} \cdot 44<\frac{9}{5}\cdot \frac{5}{9}F \le \frac{9}{5} \cdot 64\] \[\frac{9 \cdot 44}{5}<F \le \frac{9 \cdot 64}{5}\]
(79.2, 115.2]
tes
lol yes
it says thats incorrect too
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its not
^
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