Question

12<(5/9)F-32 15 years ago

Answer 1

\[12<\frac{5}{9}F-32 \le 32\]

add 32 to all sides
\[12+32<\frac{5}{9}F-32+32 \le 32+32\]
\[44<\frac{5}{9}F \le 64\]
multiply 9/5 on all sides
\[\frac{9}{5} \cdot 44<\frac{9}{5}\cdot \frac{5}{9}F \le \frac{9}{5} \cdot 64\]
\[\frac{9 \cdot 44}{5}<F \le \frac{9 \cdot 64}{5}\]

Answer 2

(79.2, 115.2]

Answer 3

tes

Answer 4

lol yes

Answer 5

it says thats incorrect too

Answer 6

its not

Answer 7

^