Question

please help me solve: (x-4)-5(x-4)^(1/2)=6 thanks!

Answer 1

i remember doing this one

Answer 2

let me see if i can find it lol

Answer 3

me too. your turn

Answer 4

think of it as a quadatic equation in
\[(x-4)^{\frac{1}{2}}\]

Answer 5

\[z^2-5z-6=0\]
\[(z-3)(z-2)=0\]
\[z=3,z=2\]
\[\sqrt{x-4}=3\] or
\[\sqrt{x-4}=2\] etc

Answer 6

http://openstudy.com/users/myininaya#/users/myininaya/updates/4e5995510b8b1f45b47b5248

Answer 7

the 'etc' being
\[\sqrt{x-4}=3\]
\[x-4=9\]
\[x=13\] or
\[\sqrt{x-4}=2\]
\[x-4=4\]
\[x=8\]

Answer 8

so my answers are wrong???

Answer 9

you factored wrong

Answer 10

lololololololol

Answer 11

(x-3)(x-2) does not equal x^2-5x-6
(x-6)(x+1)=x^2-5x-6

Answer 12

\[(z-6)(z-1)=0\]
\[z=6,z=-1\]
\[\sqrt{x-4}=6\]
\[x-4=36\]
\[x=40\] whew

Answer 13

lol

Answer 14

time to cook