Question

32^t+1=16^1-t cant seem to get the right solution

Answer 1

is 16 to the power of 1-t ??

Answer 2

yes

Answer 3

I use a common base and then distribute

Answer 4

32 = 2^5 16 = 2^4

Answer 5

that is, solve
\[5(t+1)=4(1-t)\] for t