a circle is tangent to the y axis at y=3 and has one x intercept at x=1. determine the other x intercept.

Question

amistre64 · Answer

has to be -1 i think

amistre64 · Answer

|dw:1314581338722:dw|

amistre64 · Answer

i think i seend it wrong

amistre64 · Answer

|dw:1314581398607:dw|

amistre64 · Answer

thats better

amistre64 · Answer

x^2 + y^2 = r^2

0 + 3^2 = r^2
0 + 9 = r^2

r = 3

amistre64 · Answer

and lets not forget (1,0)

x^2 + y^2 = r^2

1 + 0 = r^2

taht theiry aint gonna fly

amistre64 · Answer

(x-h)^2 + (y-k)^2 = r^2

(0-h)^2 + (3-k)^2 = r^2

(1-h)^2 + (0-k)^2 = r^2

amistre64 · Answer

h^2 + 9 + k^2 -6k = r^2

1 + h^2 -2h + k^2 = r^2

h^2 + 9 + k^2 -6k = 1 + h^2 -2h + k^2

h^2-h^2 + 9-1 + k^2-k^2 -6k = -2h

8 -6k = -2h

h = 3k -4

amistre64 · Answer

maybe?

amistre64 · Answer

i got it; the two point create a chord, whose midpoint at least is perped towards the center

amistre64 · Answer

(0,3)
-(1,0)
-----
-1,-3 ; slope = 3, midpoint = (1/2, 3/2) and a slope of -1/3

when y = 3 and y = (-1/3)x +1/(2)3 + 3/2 are the same; we got the center

amistre64 · Answer

3 = (-1/3)x +10/6

-3(3 - 10/6) = 3

-9 + 5 = x ..... missed something doh!!  process works, math is off

amistre64 · Answer

right at the beginning

 (0,3)
-(1,0)
-----
 -1,3 ; slope = -3, midpoint = (1/2, 3/2) and a slope of 1/3

3 = (1/3)x -4/3

9 = x-4

13 = x


the center should be at (13,3), which tells us that the other points is 13+12 away, or rather at (25,0)

maybe

amistre64 · Answer

soo close

amistre64 · Answer

13,3
-: 1,0
--------
  12,3 = sqrt(144+9) = sqrt(123)

sqrt(123) not= sqrt(169) were to short; lets try 12,3 to see where we go from here

amistre64 · Answer

sqrt(121+9) = sqrt(130) not= sqrt(144)

sqrt(100+9) = sqrt(109) not= sqrt(121)

sqrt(81+9) = sqrt(90) not= sqrt(100)

sqrt(64+9) = sqrt(73) not= sqrt(81)

sqrt(49+9) = sqrt(58) not= sqrt(64)

sqrt(36+9) = sqrt(45) not= sqrt(49)

sqrt(25+9) = sqrt(34) not= sqrt(36)

sqrt(16+9) = sqrt(25) = sqrt(25)

thatll do it; center is at (5,3)

amistre64 · Answer

1+5 = 5 + 4 = 9

9,0 and thats me final offer :)

(x-5)^2 + (y-3)^2 = 25

amistre64 · Answer

id have saved me self some trouble if i knew how to add :)

$$3 = \frac{1}{3}x-\frac{1}{3(2)}+\frac{3}{2}$$
$$9 = x-\frac{1}{(2)}+\frac{9}{2}$$
$$18 = 2x-1+9$$
$$18 = 2x+8$$
$$10 = 2x$$
$$5 = x$$

anonymous · Answer

The solution is incorrect. Could you please try again?

amistre64 · Answer

which "solution" did you use?

amistre64 · Answer

9,0 is the correct solution; once it is all said and done

amistre64 · Answer

http://www.wolframalpha.com/input/?i=%28x-5%29^2+%2B+%28y-3%29^2%3D25