Question

solve sin(3x)=1 on the interval [0,(2pi\3)]

Answer 1

this means
\[3x=0\] or
\[3x=\pi\] or
\[3x=2\pi\] etc

Answer 2

because those are the inputs that give 0 for sine. so divide by 3 to get
\[x=0\] or
\[x=\frac{\pi}{3}\]or
\[x=\frac{2\pi}{3}\]

Answer 3

it doesnt give me that option

Answer 4

that is because i am a moron. it says = 1 not = 0 lets try again

Answer 5

this means
\[3x=\frac{\pi}{2}\] pr \[3x=\frac{3\pi}{2}\] or
\[3x=\frac{5\pi}{2}\] etc

Answer 6

and so
\[x=\frac{\pi}{6}\]
or
\[x=\frac{\pi}{3}\] or
\[x=\frac{5\pi}{6}\] etc

Answer 7

man i must be tired. second one should be
\[x=\frac{\pi}{2}\]