Question

Find the standard equation of a circle for Radius 8, Center (3, -5)

Answer 1

which is standard?

Answer 2

im thinking its the:

(x-Cx)^2 + (y-Cy)^2 = r^2

Answer 3

where Center = (Cx,Cy)

Answer 4

I don't know- says find the standard equation of a circle that satisfies the
conditions.

Answer 5

(x -3)^2 + (y+5)^2 = 8^2
x^2 -6x +9 +y^2 +10y +25 = 64
x^2 +y^2 -6x +10y -30 = 0

Answer 6

in other words, it wants you to know what the standard equation from looks like

Answer 7

i cant recall if its the tight one or the loose one

Answer 8

OK- Thanks! Looks like Ritas response might be the one.

Answer 9

could be :) thats the loose form, its got a few extra pieces hanging off it

Answer 10

is the tight one easier to follow?