Mathematics
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OpenStudy (anonymous):
solve the equation for x square root of x-3= 4 show work?
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OpenStudy (anonymous):
square both sides
OpenStudy (anonymous):
\[x^{2}+9=16\]
OpenStudy (anonymous):
that doesnt work?
OpenStudy (anonymous):
If u square a square root, you get what is under the radical
OpenStudy (anonymous):
x * sqrt(x-3) - square this
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OpenStudy (anonymous):
No, it's just sqrt(x-3)
OpenStudy (anonymous):
sqrt(x-3)=4 i need to find out what x is
OpenStudy (anonymous):
Square it..
OpenStudy (anonymous):
If u square a square root, you get what is under the radical
OpenStudy (anonymous):
still have no idea what you mean?
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OpenStudy (anonymous):
eq root 2 squared is 2
OpenStudy (anonymous):
\[\sqrt{number^2}=number\]
OpenStudy (anonymous):
True, but different to here...
OpenStudy (anonymous):
\[(\sqrt{number})^2=number\]
OpenStudy (anonymous):
\[\sqrt2^2 =2\]
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OpenStudy (anonymous):
\[\sqrt{x-3}^2 =\]
OpenStudy (anonymous):
oh ok i got \[x=13 \] because \[\sqrt{13+3}=\sqrt{16}=\]
OpenStudy (anonymous):
4
OpenStudy (anonymous):
is that correct?
OpenStudy (anonymous):
x-3 is the left hand side squared, agree?
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OpenStudy (anonymous):
\[\sqrt{x+3}^{2}\]
OpenStudy (anonymous):
is that what you are asking
OpenStudy (anonymous):
What's that?
OpenStudy (anonymous):
Here is your question
square root of x-3= 4
OpenStudy (anonymous):
yes that is the problem
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OpenStudy (anonymous):
Do you agree that the square of the left hand side is x-3?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
x-3=16 x=19
OpenStudy (anonymous):
And the square of the right hand side is 16.
OpenStudy (anonymous):
mathballet is a genius!
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OpenStudy (anonymous):
thx
OpenStudy (anonymous):
How did u do it?
OpenStudy (anonymous):
im even more confused
OpenStudy (anonymous):
\[\sqrt{x-3}=4\]
\[ x-3= 4^{2}\]\[x-3=16\]
OpenStudy (anonymous):
I believe this is where we had got to before the interruption.
x-3=16
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OpenStudy (anonymous):
x=16+3 x=19
OpenStudy (anonymous):
duz it help
OpenStudy (anonymous):
SO mathballet used considerable math expertise in transferring the 3 to the other side.
OpenStudy (anonymous):
it is x+3 not x-3 in the sqrt
OpenStudy (anonymous):
crap i wrote it wrong
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OpenStudy (anonymous):
but u posted sqrt x-3
OpenStudy (anonymous):
ok it is \[\sqrt{x+3}=4\] what is x
OpenStudy (anonymous):
That looks familiar, third time lucky?
OpenStudy (anonymous):
that is the problem sorry :D
OpenStudy (anonymous):
square it..
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OpenStudy (anonymous):
=\[\sqrt{x+3}=16 \] yes?
OpenStudy (anonymous):
U have squared a square root, that get's rid of the square root.
OpenStudy (anonymous):
\[ x+3= 4^{2}\]
OpenStudy (anonymous):
x+3=16
OpenStudy (anonymous):
x=16-3 x=13
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OpenStudy (anonymous):
so it is just \[x+3=16\]
\[x=16-3=13 \]
x=13
OpenStudy (anonymous):
yay i got it right thanks a lot
OpenStudy (anonymous):
\[\huge \checkmark\]
OpenStudy (anonymous):
yup
OpenStudy (anonymous):
Actually..
\[\sqrt{a^2} = |a|\]
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OpenStudy (anonymous):
But it works out fine in this case.