Question

solve the equation sqrt x+12=x

Answer 1

is it all (x+12) under sqr?

Answer 2

yes

Answer 3

\[\sqrt{x+12}=x\]

Answer 4

that is what it looks like

Answer 5

raise to the 2nd power both sides
x+12-x^2=0
do u know how to go further?

Answer 6

somewhat

Answer 7

D=b^2-4ac

Answer 8

do u own a graphing calculator?

Answer 9

\[ x+12= x^{2}\]

Answer 10

\[x^{2}-x-12=0\]

Answer 11

\[\sqrt{x+12}\]
\[\sqrt{x+12}^{2}=x ^{2} \]
\[x+12=x^2\]

Answer 12

(x-4)(x+3) x=4 and -3

Answer 13

@mathballet how did you get that

Answer 14

plug in to check for extraneous

Answer 15

move the x^2 over to the other side correct

Answer 16

brought everything to one side

Answer 17

no dont move x^2

Answer 18

\[-x^2 + x + 12 = 0;\ x \ge -12\]

Answer 19

so move x+12

Answer 20

You can move to either side.

Answer 21

You get the same results.

Answer 22

move x and 12

Answer 23

Jenni, you're fine moving the x^2 if you'd rather. You get the same thing.

Answer 24

its easier when factoring if u move x and 12

Answer 25

Ah, yeah. if you're going to factor it's easier if you have a positive coefficient.

Answer 26

ok so its (x+3)(x+4)?

Answer 27

(x+3)(x-4) = 0

Answer 28

(x-4)(x+3)

Answer 29

but that would make -x-12+x^2=0

Answer 30

if i move the x+12 to the other side

Answer 31

xactly