Eliminate the parameter t AND write the rectangular equation for x = t2+3 and y = 2t.
CORRECTION: x= t^2+3
t=y/2
x= y^2/4 +3
I'm confused....i got t = sqrt of 3-x.
\[x=\frac{y^2}{4}+3\] 4 x = y^2 + 3 4x-3=y^2
then you have to use plus or minus i think. that is why iman solved the other way. correct me if i am wrong
can u explain how you got x = y^2/4 =3
y=2t t=y/2 t^2 = y^2/4
Oh i see...but what is a rectangular equation??
where you equation is like y=f(x)
as opposed to parametric equation where both x and y depend on t
so is the solution to the question 4x-3=y^2 or something else
y^2=4x-3 take square root of both side \[y=\pm \sqrt{4 x-3}\]
ok...i get it now...thanks..is that the end of the problem
yes, relieved?
yup! the question was worded to weirdly...i wasnt evn sure what it was asking
can you help me with anotehr q?
sure , but post it as new question
ok...ill post it now
http://openstudy.com/groups/mathematics#/groups/mathematics/updates/4e5c4ca70b8b1f45b48ab692
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