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Use the quadratic formula to solve the equation x^2+2x-1=0?
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a = 1 b = 2 c = -1 substitute them into formula
\[x = \frac{-b \pm \sqrt{b^{2}-4ac}}{2a}\]
find b^2-4ac in the general form of quadritic equation i.e. ax^2+bx+c=0
that seems the roots of the equations would be imaginary ones
Okay, so I got -2+or-sqrtof eight/2. Now what?
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I/m sorry the two roots are real
x1= -1+sqrt(2)
x2=-1-sqrt(2)
@poffdiddy you can factor out a 2 -> sqrt(8) = 2sqrt(2) -> 2(-1 +- sqrt(2))/2 = -1 +- sqrt(2)
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