Question

i gotta write up a bunch of derivatives for "homework"; is there a place that i can latex it up and it spits out the text to print it?

Answer 1

write the basic derivatives like
d/dx (sin x) = cos x

Answer 2

\[y=cos(tan(x))\]\[y' = -sin(tan(x))sec^2(x)\]

Answer 3

Latexlab

Answer 4

not sure what you mean. if you write the latex your editor will convert to pdf right?

Answer 5

http://docs.latexlab.org/

Answer 6

\sin
gets rid of the italics

Answer 7

I think I misunderstood.

Answer 8

i that is kind of cool. web based editor using google docs?

Answer 9

Yup, not bad either...

Answer 10

lol ... just write the basic derivatives ... i almost wet myself on that one

Answer 11

and you want to print them out right?

Answer 12

yes, my handwriting is not good for turning in math homework :)

Answer 13

i could have written that up as begin{align} i think and forgone most of thos y's

Answer 14

ah How did you do that estudier

Answer 15

In my Firefox, if right click, as well as show source u can choose format MathML and copy that instead.

Answer 16

I can do that too

Answer 17

That's how I did, copy and paste into blank file with .html extension

Answer 18

okay Got it.
Thank You estudier

Answer 19

@amistre why not just use latex editor?

Answer 20

That's the other way, probably quicker than taking from here..

Answer 21

and @ estudier, this doesn't seem to like $ command for in line math. that is what i use. is there another way?

Answer 22

Which?

Answer 23

the google docs

Answer 24

hehe It worked

Answer 25

U can set it up to compile with your distribution...

Answer 26

Compiler..settings

Answer 27

i am happy with texmaker
works quickly and easily and i don't even compile. just go to preview and then have the option to view in "external view" save a copy and voila

Answer 28

Yes, I think for ur own stuff, on your own pc is fine.

Other is better for online storage and sharing....

Answer 29

Still not exactly clear what Amistre wanted though...

Answer 30

i want: to be able to type pretty looking equations instead of the:

y' = e^x[(x+1)/(x-1)]^2 that ascii produces :)

Answer 31

thats the review from your "test.html"

Answer 32

OK, it is browser problem, math fonts needed.

Ishaan and I have Firefox, they are built in.

Answer 33

type it in to google docs that estudier sent. that is what i did. worked pretty well

Answer 34

did you see the pdf i sent? it is what you wrote

Answer 35

the pdf is nice; need to left align in tho

Answer 36

i just copied what you wrote, compiled and converted to pdf .
let me see if i can align left

Answer 37

i cant recall the align commands at the moment :)

Answer 38

http://en.wikibooks.org/wiki/LaTeX/Advanced_Mathematics

Answer 39

i usually just use $ but it doesn't seem to work here

Answer 40

Multiline, gather, align are at that link...

Answer 41

some of these are not working for me in google doc. if you really want to use latex probably easier to use latexmaker or some other editor

Answer 42

Try development version (menu at top)

Answer 43

too hard for me

Answer 44

i am going to get this for sure

Answer 45

i figure i can type it out here to preview it, and take it someplace else to form it into a printable version :)

Answer 46

i got it !

Answer 47

not bad but i can't figure out why the first line is not displaying in math mode

Answer 48

i used the google doc link estudier sent, copied and pasted, compiled, and then viewed in pdf

Answer 49

btw \tan gets rid of italics

Answer 50

i like the italics, makes me feel like im writing in cursive ;)

Answer 51

you want these i will copy and paste them for you

Answer 52

just put \sin(x) or \tan(x) will get rid of cursive

Answer 53

yeah, my end goal is to get them into a file that I can print out :) thnx

Answer 54

i got one more ....

Answer 55

.... and they all lived happily ever after, the end :)

Answer 56

oh i missed the last two hold on

Answer 57

the aligns didnt match up on the pdf .... my (=)s are all over the place, other than that it looks good, barring the last 2 o course

Answer 58

i saved it to me desktop but it wont let me edit it to move them over any

Answer 59

that is because i sent a pdf

Answer 60

last two are messing up. let me open a new doc and try them

Answer 61

i can't seem to make the last two work

Answer 62

if anything that should be all the latex in one fell swoop

Answer 63

there are a few delimiters that might not show in the "source" for 52 and 56

Answer 64

ack!! ... i thought id source up as a whole, but its still in pieces :)

Answer 65

yeah there is something up. let me see if i can figure i tout

Answer 66

the first batch worked no problem

Answer 67

\begin{align}
2)\ y&=cos(tan(x))\\
y'&=-sin(tan(x))\ sec^2(x)\\
\\
4)\ y&=\frac{3x-2}{\sqrt{2x+1}}\\
y'&=(3x-2)'(2x+1)^{-1/2}+(3x-2)(2x+1)'^{-1/2}\\
&=3(2x+1)^{-1/2}\ +\ (3x-2)\frac{-2}{2}(2x+1)^{-3/2}\\
&=(2x+1)^{-3/2}\left(3(2x+1)-(3x-2)\right)\\\\
&=\frac{6x+2-3x+2}{(2x+1)^{3/2}}\\\\
&=\frac{3x+5}{(2x+1)^{3/2}}\\\\\\\\
6)\ y&=\frac{e^x}{1+x^2}\\\\
y'&=\frac{e^x(1+x^2)-e^x(2x)}{(x^2+1)^2}\\\\
&=\frac{e^x+e^xx^2-e^x2x}{(x^2+1)^2}\\\\
&=e^x\frac{x^2-2x+1}{(x^2+1)^2}\\\\
&=e^x\frac{(x^2-1)^2}{(x^2+1)^2}\\\\
&=e^x\left(\frac{x^2-1}{x^2+1}\right)^2\\\\
8)\ y&=e^{-t}(t^2-2t+2)\\
y'&=e'^{-t}(t^2-2t+2)+e^{-t}(t^2-2t+2)'\\
&=-e^{-t}(t^2-2t+2)+e^{-t}(2t-2)\\
&=-e^{-t}\left((t^2-2t+2)-(2t-2)\right)\\
&=-e^{-t}(t^2-2t+2-2t+2)\\
&=-e^{-t}(t^2-4t+4)\\
&=-e^{-t}(t-2)^2\\\\\\
10)\ y&=e^{mx}cos(nx)\\\\
y'&=e'^{mx}cos(nx)+e^{mx}cos'(nx)\\
&=me^{mx}cos(nx)-ne^{mx}sin(nx)\\
&=e^{mx}(m\ cos(nx)-n\ sin(nx))\\\\\\
14)\ y&=\frac{1}{sin(x-sin(x))}\\\\
&=(sin(x-sin(x))^{-1}\\\\
y'&=-(sin(x-sin(x))^{-2}\ cos(x-sin(x))\ (1-cos(x))\\\\
&=\frac{cos(x-sin(x))\ (1-cos(x))}{-sin^2(x-sin(x))}\\\\
&=\frac{cos(x-sin(x))\ (cos(x)+1)}{sin^2(x-sin(x))}\\\\\\
&=\cot(x-sin(x))\ \ (\cos(x)+1)\ \ \ csc(x-sin(x))\\\\
16)\ y&=ln(csc(5x))\\\\
y'&=\frac{-5csc(5x)cot(5x)}{csc(5x)}\\\\
&=-5cot(5x)\\\\
20)\ y&=ln(x^2e^x)\\\\
y'&=\frac{x'^2e^x+x^2e'^x}{x^2e^x}\\\\
&=\frac{2xe^x+x^2e^x}{x^2e^x}\\\\
&=\frac{2x+x^2}{x^2}\\\\
&=\frac{2+x}{x}\\\\
22)\ y&=sec(1+x^2)\\\\
y'&=2x\ sec(1+x^2)\ tan(1+x^2)\\\\
26)\ y&=\sqrt{sin(\sqrt{x})}\\\\
y'&=\frac{cos(\sqrt{x})}{2\sqrt{sin(\sqrt{x})}}*\frac{1}{2\sqrt{x}}\\\\\\
&=\frac{cos(\sqrt{x})}{4\sqrt{x\ sin(\sqrt{x})}}\\\\
32)\ y&=e^{cos(x)}+cos(e^x)\\\\
y'&=-sin(x)\ e^{cos(x)}-e^x\ sin(e^x)\\\\
44)\ y&=\frac{sin(mx)}{x}\\\\
y'&=\frac{x*sin'(mx)-sin(mx)x'}{x^2}\\\\
&=\frac{mx\ cos(mx)-sin(mx)}{x^2}\\\\
52)\ &\ g(t)=t\ sin(t)\text{; find }g''(\frac{\pi}{6})\\\\
\\
\ \ \ g(t)&=t\ sin(t)\\\\
g'(t)&=t'sin(t)+t\ sin'(t)\\\\
&=sin(t)+t\ cos(t)\\\\
g''(t)&=sin'(t)+t'\ cos(t)+t\ cos'(t)\\\\
&=cos(t)+cos(t)-t\ sin(t)\\\\
&=2cos(t)-t\ sin(t)\\\\
g''(\frac{\pi}{6})&=2cos(\frac{\pi}{6})-\frac{\pi}{6}\ sin(\frac{\pi}{6})\\\\
&=2(\frac{\sqrt{3}}{2})-\frac{\pi}{6}*\frac{1}{2}\\\\
&=\sqrt{3}-\frac{\pi}{12}\\\\
58)\ &\text{ Find the equation of the tangent line @ (0,-1).}\\\\
\ \ \ \ \ \ y&=\frac{x^2-1}{x^2+1}\\\\\\
y'&=\frac{2x(x^2+1)-2x(x^2-1)}{(x^2+1)^2}\\\\
&=\frac{2(0)(0^2+1)-2(0)(0^2-1)}{(0^2+1)^2}=0\\\\\\
&\text{The equation of the tangent line @ (0,-1) is:}\ \ y=-1
\end{align}

Answer 68

thats all on one block now

Answer 69

let me try that

Answer 70

That came out ok on a web page..

Answer 71

its due tomorrow, so no real rush; i gotta go to discrete at the moment; thnx and good luck. I got the textbook in the mail yesterday, again thank you for letting me have it, i really do appreaciate it :)

Answer 72

everything is good but it is rendering your text in italicx

Answer 73

might need to amend the texts as what \textff or something?

Answer 74

i use \text{} which is what you used

Answer 75

if it was me i would say close enough for government work

Answer 76

if this shows up, this is what i ended up with.

I took a screenshots and saved each question in its own picture file on paint; then inserted the pictures in a MSWord doc, and printed :)