Question

simplify sqrt 150x^5y^8

Answer 1

5x^2y^8sqr(6x)

Answer 2

how did you get that

Answer 3

\[\sqrt{150x ^{5}y ^{8}}\]

Answer 4

sqr(25*6*x^4*x*[y^(4)]^2)=5x^2y^4sqr(6x) sorry

Answer 5

what does that say can you make it a formula so i can know what you are talking about please

Answer 6

i have expressed 150=25*6
x5=x^4*x
y^8=(y^4)^2

Answer 7

ok and how would i get the answer based on what you have given me

Answer 8

by sqrooting them
sqr(25*6)=5sqr6
sqr(x^4*x)=x^2sqrx
sqr{[y^4]^2}=y^4
W8 for Radar's answer though

Answer 9

whr did sqr30x come from?

Answer 10

shouldn't it b sqt6x?

Answer 11

Those had to remain within the radical as they were not perfect squares.

Answer 12

only 6 remains under sqr....right? O.o

Answer 13

You are right, I mistook the 5 for a constant in the radical rather than an exponent, although I treated it as an exponent also lol Duh!\[5x ^{2}y ^{4}\sqrt{6x}\]

Answer 14

phew :D :D

Answer 15

Since it was \[x ^{5}=x ^{4}x ^{1}\]You still had a x left in the radical;

Answer 16

so it is \[5x^2y^4\sqrt{6x}\]

Answer 17

that is the correct answer

Answer 18

yes tht's it :)

Answer 19

I agree also, good luck with these things.

Answer 20

thanks