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Simplify the answer: (Question to come in following post)
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\[\frac{-42x^{3}y^{5}(x^{2})^{4}}{36x^{3}y^{7}}\]
\[\frac{-42(x^{2})^{4}}{36y^{}}\]
\[= \frac{-42x^{8}}{36y^{2}}\] is I believe my final answer.
-7x^8 / 6y^2
Oh, right. I forgot to actually simplify the values, not just the variables. But the x and y's are all correct exponents?
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second post incorrect - oh u corrected it - you can simplify further to 7x^8 / 6y^2
-7
yes, your x and y values are right
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