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Mathematics 16 Online
OpenStudy (anonymous):

How do you find domain and range?

OpenStudy (amistre64):

domain is the values of a funtion/relation which can be used "legally" in the equation being defined

OpenStudy (amistre64):

range is the outputs that are a result of the domain

OpenStudy (anonymous):

That didn't help??? Isn't there an equation?

OpenStudy (amistre64):

|dw:1314829122814:dw|

OpenStudy (anonymous):

The domain of a function \(f(x)\) is the possible values for x that produce a value for \(f(x)\). The range of the function is all the possible values for \(f(x)\)

OpenStudy (amistre64):

a function is often times defined as an equation; but as far as domain and range go, no there doesnt have to be a defined function at all

OpenStudy (anonymous):

find the domain and range of the equation y=-2+(the square root) of x

OpenStudy (amistre64):

for instance: f(x) = 1/x is defineing a function by an equation; and this equation is not defined for x=0 is it?

OpenStudy (amistre64):

so the domain will be all numbers except for 0

OpenStudy (amistre64):

the controling part of the equation that you have is "sqrt(x)"

OpenStudy (anonymous):

\[f(x) = \cases{\begin{array}{ccc} 2 & \text{if} & x = 5\\ 7.3 & \text{if} & x = 27 \\ 8 & \text{if} & x \text{ is an even number. }\end{array}}\]

OpenStudy (amistre64):

since sqrt(-#) is not defined on a "real" number line; we have to maintain all values of x that are equal to or greater than 0

OpenStudy (anonymous):

(-infinity to 0) (0 to infinity)

OpenStudy (anonymous):

The domain for the function I defined above will be {5, 27, all even numbers}. The range is {2,7.3, 8}

OpenStudy (amistre64):

|dw:1314829339642:dw|

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