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Verify the following identity: sin(theta)cos^2(theta)+sin^3(theta)=sin(theta) Please include steps! :/ Thank you!
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split it all into sins
cos^2 = 1 - sin^2 right?
rightt
then distribute the sin thru and cancel the ^3s
make sense?
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ehh, im not good with trig :/
the trig itself isnt the issue; they want you to become familiar with identites; this really just reads as this: ab^2 - a^3 = a ; when b^2 = 1-a^2 a(1-a^2) - a^3 = a a -a^3 + a^3 = a a = a
cos^2 = 1 - sin^2
mkay, so far i get that..
sin*cos^2 + sin^3 = sin ; and cos^2 = 1-sin^2 sin*(1-sin^2) + sin^3 = sin sin -sin^3 + sin^3 = sin sin = sin helps if i dont typo it
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thank you so much!
yep
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