Question

factor completely x^(17/3)-25x^(11/3)

Answer 1

is it x^(11/3)(x-5)(x+5)

Answer 2

You should learn how to use the equation editior. I'm having trouble interpreting your math

Answer 3

basically the problem is x to the 17/3 power minus 25x to the 11/3 power

Answer 4

bizzarro

Answer 5

Doesn't this involve logs?

Answer 6

According to wolfram, your answer is correct. I'm still scratching my head though

Answer 7

How did you get your answer?

Answer 8

the x to (11/3) power im not sure thats the problem lol

Answer 9

how do you use wolframalpha?

Answer 10

I think I know how it is done

Answer 11

apparently you factor out x^11/3 leaving you with x^(11/3)(x^2 - 25)

then that becomes x^(11/3)(x + 5)(x - 5)

Answer 12

somehow when you factor out the x^(11/3) you end up with (x^(6/3) - 25) which becomes (x^2 - 25)

Answer 13

I guess because 17/3 - 11/3 = 6/3

Answer 14

To use wolfram alpha, write:

solve(x^(17/3)-25x^(11/3)=0,x)

Answer 15

But even the steps for that is kind of shoddy. I don't like it

Answer 16

okay thanks very much