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find the derivative of f(x)=cosπx^2
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\[f(x)=\cos(\pi)x^2 or f(x)=\cos(\pi x^2) or f(x)=(\cos(\pi x))^2\] which is it?
the second one I think because the book doesn't have any parenthesis at all
\[f(x)=\cos(\pi x^2) => f'(x)=(\pi x^2)'[(\cos')(\pi x^2)]=\pi (x^2)'[(\cos')(\pi x^2)]\]
\[f'(x)=\pi (2x)(-\sin(\pi x^2))\]
\[f'(x)=-2\pi x \sin(\pi x^2)\]
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what rule did you use?
chain rule do you not see i took the derivative of the inside and multiplied by derivative of outside?
\[f(x)=h(g(x))=\cos(\pi x^2) => h(x)= \cos(x) , g(x)=\pi x^2\] \[f'(x)=g'(x)h'(g(x))=2\pi x(-\sin(g(x)))=2\pi x(-\sin(\pi x^2))=-2 \pi x \sin(\pi x^2)\]
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