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find the difference quotient of f; that is, find f(x+h)-f(x) over h. f(x)= 4x+3
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wrong problem. its f(x)= x^2-x+4
Oh cool, I get to do all of that all over again....
the answer is f ' (x) f(x) = x^2 - x + 4 f ' (x) = 2x - 1
NO, difference quotient is not the same as derivative
The limit of the difference quotient as h goes to zero is the derivative....but not the difference quotient itself
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I don't feel like re-writing all of that all over again
well get off.. i need somebody that can help m
me*
Get off? Am I on a train? lol
Is that how you normally talk to people attempting to help you?
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