Question

car was going 70mph then when it stop it went 177ft. how much will car go if it stops at 15 mph and 130 mph

Answer 1

it was wrong.. the stopping distance is proportional to the square of the velocyity

Answer 2

oh!!!!

Answer 3

you didnt say that
so we have

s = k * v^2 where k is a constant
we find k by plugging in the values v=70 and s = 177
177 = k * 70^2
k = 177/70^2 = 0.0361
so the formula relating stopping distance and velocity is

s = 0.0361v^2
so plug in v=15
s = 0.0361 * 15^2
= 8 ft
to find s for 130 mph plug in v=130

Answer 4

does feet and mile matter?

Answer 5

no

Answer 6

if u convert to ft you'll get the same answer but the value of k will differ - and you'll be dealing with BIG numbers

Answer 7

thank you master