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(4k^2)(2k^2)
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8k^4
do you understand how this works patrycjaa ?
kind of.. i just multiply each of them right?
you multiply the numbers and add the exponents for the variables
what would i do when i divide? for example 7p3/2p4
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\[4*k^2*2*k^2=4*2*k^2*k^2=8*k ^{(2+2)}=8*k ^{4}\]
that would be subtracting exponents when dividing and actually dividing the numbers if you can
so my answer would be 3.5^ -1?
no u can leave as 7 --- 2p
instead of a decimal
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To clarify why we add the exponents when multiplying: \[k ^{2}*k ^{4}=(k*k)*(k*k*k*k)=k ^{(2+4)}=k ^{6}\] And here is an example to explain why we subtract exponents in division: \[\frac{k ^{6}}{k ^{3}}=\frac{k*k*k*k*k*k}{k*k*k}=k ^{(6-3)}=k ^{3}\]
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