Question

When an irregularly shaped chunk of a semiconductor weighing 8.719 g was placed in a graduated cylinder containing 24.00 mL of water, the water level in the cylinder rose to 28.49 mL. What is the density of this substance in g/cm3?

Answer 1

Ahm - as the problem uses a graduated cylinder, I think we can assume, that the semiconducter "chunck" is completetly under water.
Does anybody disagree? (not absolutely sure about this..)

So the displacement of the water gives us the volume of the semiconductor.\[\Delta V = V_2 - V_1 = 28.49ml - 24.00ml = 4.49ml \] One litre is equal to 0.001 m³, so 4.49ml are equal to 4.49cm³.

\[\rho = {m \over V} = {8.719g \over 4.49cm^3} \approx 1.942 {g \over cm^3} = 1942 {kg \over m^3}\]