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The inequality –x2 + x – 10 < – 2x2 – 4 is satisfied if...
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\[-x ^{2}+x-10<-2x ^{2}-4\]
\[x^2-x-6<0\] \[(x-3)(x+2)<0\] and since this is a parabola that opens up, it will be negative between the zeros so answer is \[(-2,3)\]
x^2+x-6<0 ===> (x-2)(x+3) <0 ==> solution interval = (2,3)
I mean (-3,2)
The answer key says -3<x<2.
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raheen is right i am wrong i wrote -x when it should be +x
I guess I was supposed to use the coordinates to make an inequality statement
no no that is not a coordinate!
Ah, right, because they're both domains
thats means \[\{x|-3<x<2\}\]
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Yes, thanks for your help :)
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