diameter of ferris wheel is 80 ft.
a) if the ferris wheel made one revolution every 45 second , find the linear velocity of a person riding in the ferris wheel b) suppose the linear velocity of person riding in the ferris wheel is 8 feet per second .What is the time for one revolution of the ferris wheel ?
(a) Distance traveled in one revolution (circumference) = \[2\pi r = 2\pi \times 80ft = 502.65ft\] Time elapsed in one revolution = 45 seconds. \[\frac{502.65ft}{45s} = 11.17ft/s\] (b) \[\frac{502.65ft}{8\frac{ft}{s}} = 62.83s\]
Oh wait, the diameter is 80 ft, I was using r=80ft
(a) 5.585ft/s (b) 31.416s
I think you right from begining d= diameter * pi
=80*pi
Well I was doing 2*pi*80 because I thought 80 was the radius, when it only should have been pi*80
80*pi=251.33?
I don't get b ?
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