Wanted to ask how to prove "B'BA=B'BC is equivalent to BA=BC"....thx
No, because you can just cancel out the same matrix on the premise that it is invertible.
You can also multiply both sides by B, and then add some parentheses (associative property holds). BB'BA=BB'BC (BB')BA=(BB')BC
@crazydoglady yes, but you can only imply BA=BC if (BB') is invertible. And A and C have to be n x k, where n = number of columns of B and k is any number of cols.
How is the question written means "A1 iff A2" where A1:"B'BA=B'BC" and A2 : "BA=BC" as was mentioned by others here A2 implies A1 by pre-multiply both sides of BA=BC by B', however the other implication is not always true, should be true if as was mentioned by NGOG (BB') or B should be invertible
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