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MIT 18.06 Linear Algebra, Spring 2010 16 Online
OpenStudy (anonymous):

Wanted to ask how to prove "B'BA=B'BC is equivalent to BA=BC"....thx

OpenStudy (anonymous):

No, because you can just cancel out the same matrix on the premise that it is invertible.

OpenStudy (anonymous):

You can also multiply both sides by B, and then add some parentheses (associative property holds). BB'BA=BB'BC (BB')BA=(BB')BC

OpenStudy (anonymous):

@crazydoglady yes, but you can only imply BA=BC if (BB') is invertible. And A and C have to be n x k, where n = number of columns of B and k is any number of cols.

OpenStudy (anonymous):

How is the question written means "A1 iff A2" where A1:"B'BA=B'BC" and A2 : "BA=BC" as was mentioned by others here A2 implies A1 by pre-multiply both sides of BA=BC by B', however the other implication is not always true, should be true if as was mentioned by NGOG (BB') or B should be invertible

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