Question

how would i graph this x+4y=8

Answer 1

If you let x=0 you would get 4y=8 or y=2, thus one point would be (0,2). If you let y=0 you would get x=8, thus a second point would be (8,0). You only need two points to graph a line. So plot those two points and draw a line between them and extend it in both directions.

Answer 2

See attachment

Answer 3

You can graph this by converting into y = mx + b format..so:
x + 4y = 8
4y = -x + 8
y = -x/4 + 8/4
y = -x/4 + 2

Now since you know the y-intercept should be 2 make a point on the y-axis at 2.
The slope in this case is -1/4 so you would go down one and right 4..and keep going down 1 right 4 until you create a long enough line =)

Answer 4

Or what K^2 wrote!

Answer 5

LOL K^2 :P

Answer 6

who's right

Answer 7

Lol we both are, just explained in different terms =)

Answer 8

Notice that if you let x=0 on K^2's equation that y still equals 2. There are two basic forms for the equation of a line ax+by=c (Yours in this problem) and y=mx+b the one K^2 converted it into. Either will give the same graph.