Question

Solve for θ.

Answer 1

For which problem?

Answer 2

crap hang on.

Answer 3

\[mg \sin \theta = \mu mg \cos \theta ((M+m)/(m))\]

Answer 4

divide both sides by cos(theta) and divide both sides by mg

Answer 5

tan(theta)mg=um(M+m)/m
tan(theta)=u(M+m)/m
theta=tan^-1(u(M+m)/m)
someone check me

Answer 6

then you get
\[\frac{\sin(\theta)}{\cos(\theta)}=\mu \frac{\not{m}\not{g}}{\not{m}\not{g}} \frac{M+m}{m}\]

Answer 7

\[\tan(\theta)=\mu \frac{M+m}{m} => \theta=\tan^{-1}(\mu \frac{M+m}{m})\]

Answer 8

whoa where di tan theta come from?!?!

Answer 9

*did

Answer 10

divided both sides by cos(theta) because remeber sin/cos=tan from trig?

Answer 11

oh ok its been awhile lol

Answer 12

i know we all have that moment, haha