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suppose (-6,2) is a point on the graph of y=g(x). what point is on the graph of y=-4g(x-7)+1
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if x = 1 you get \[-4\times g(1-7)+1=-4\times g(-6)+1=-4\times 2+1=-8+1=-7\]
if g(-6)=2 then if x-7=-6 >x=1 so y=-4g(1-7)+1=-4g(-6)+1=-4(2)+1=-8+1=-7
so \[(1,-7)\] is on the graph of \[-4g(x-7)+1\]
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