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how do you solve : (root3+root2)^2 ?
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a square root squared is just a normal number
so it would be 3+2=5
Ah I see, thank you :)!
omg wait jim
oh wait, nvm lol
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there is a mistake
i know, just caught it lol
you actually made one
i cannot believe this
\[\large (\sqrt{3}+\sqrt{2})^2\] \[\large (\sqrt{3})^2+2\sqrt{3}\sqrt{2}+(\sqrt{2})^2\] \[\large 3+2\sqrt{6}+2\] \[\large 5+2\sqrt{6}\] So \[\large (\sqrt{3}+\sqrt{2})^2=5+2\sqrt{6}\]
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ok very good! :) lol
small mistake with radicals = radical mistake...wait a minute....
:,( my answer was completely and foolishly wrong...
lol poor gandalf
you shall not pass...lol
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lol! I still get to save middle earth though...
good point...
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