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OpenStudy (anonymous):
how about
\[(2z+3)(4z-5)\]
OpenStudy (anonymous):
how did u get it
OpenStudy (anonymous):
One method is factor by grouping you multiply 8(-15) and you get -120 then you look for two factors of -120 that add up to the middle coefficient of your expression 2. That will be -12 and 10
OpenStudy (anonymous):
thats the only part i understand i dont know how to break it down?
OpenStudy (anonymous):
a) trial and error
b) find the zeros
c) factor by "grouping" whatever that is
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OpenStudy (anonymous):
So you rewrite your equation as:
(8z^2 -12z) + (10z - 15)
And take the GCF of the both sides
4z(2z - 3z) + 5(2z - 3)
(2z - 3)(4z + 5)
OpenStudy (anonymous):
@nayeaddo, you can explain better than i can but it should be 12 and -10 right?
OpenStudy (anonymous):
Ugghh lol I messed up its 12 and -10 yes you're right.
OpenStudy (anonymous):
lol ok
OpenStudy (anonymous):
do you get it though?
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OpenStudy (anonymous):
i dont know how to break it down after i put -10 and 12 into it