8z^2+2z-15 factor
how about \[(2z+3)(4z-5)\]
how did u get it
One method is factor by grouping you multiply 8(-15) and you get -120 then you look for two factors of -120 that add up to the middle coefficient of your expression 2. That will be -12 and 10
thats the only part i understand i dont know how to break it down?
a) trial and error b) find the zeros c) factor by "grouping" whatever that is
So you rewrite your equation as: (8z^2 -12z) + (10z - 15) And take the GCF of the both sides 4z(2z - 3z) + 5(2z - 3) (2z - 3)(4z + 5)
@nayeaddo, you can explain better than i can but it should be 12 and -10 right?
Ugghh lol I messed up its 12 and -10 yes you're right.
lol ok
do you get it though?
i dont know how to break it down after i put -10 and 12 into it
Okay so you have: (8z^2 -10z) + (12z - 15) 2z(4z - 5) + 3(4z - 5) (4z - 5)(2z + 3)
The order of -10z + 12z doesn't matter because: -10z + 12z = 12z - 10z = 2z
ok thanks
you're welcome
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