Find the equation of the line that runs parallel to x-5=0 and passes through the point (8,6).
how do i find slope?
x=8
no slope, line is vertical
what tracy said
so how would i write the equation?
just have no slope?
the slope is 0 because x-5=0 is a vertical line. You would write the parallel line as x=8
but if it asks for the equation just do y-6=(x-8) or is there no equation because there is no slope
the equation y-6=(x-8) has a slope of 1
@tracy slope of course is not zero it is undefined
slope of \[y=2\] is zero slope of \[x=5\] does not exist
oh yea sorry, horizontal lines have slope=0
so that line is undefined because its slope is non existent?
there is no equation of that line?
It's not a vertical line lol...my bad
no it has an equation. the equation for vertical line looks like \[x=\text{some number}\]
it just doesn't have a slope, so you cannot for example use the point slope formula
so the equation would simply be x=8
no, it's y = x-5, with a slope of 1/1x - 5, -5 is the y-intercept.
y = mx+b m is slope, b is y-intercept. we can put this equation in: 0 = 1x+(-5) y = 0, m = 1, b = -5.
No, because y is a variable. The original equation has x=5 even when y is not 0. Your equation works at that point, but is not parallel to x-5 = 0.
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