Question

is the answer to
x^2+7x+10......(x+2)(X+5)?

Answer 1

yes , it's correct factoring

Answer 2

Coorect =)

Answer 3

thank you just checking my work

Answer 4

great and you are welcom. keep on!

Answer 5

how do i solve x^2-10x+21? i came up with (x-10) (x-1) what did i do wrong?

Answer 6

(x-7)(x-3)

Answer 7

First: factor x^2 into ( x ) (x )

Answer 8

then take the last term i.e +21 , and first check the sign og the middle term

Answer 9

if its sign minus ==> we got _ and - in both brackets since our last sign +

Answer 10

and by trail and error method we reach to the right factorization

Answer 11

and with keeping practicing, it would'nt take much to find it vere easy.

Answer 12

so is x^2+4x -32.....(x+4)
(x-8)?

Answer 13

it should be (x-4)(x+8) , I'll try to draw it to you too.

Answer 14

is 2x^2+5xy-12y^2 prime?

Answer 15

is 2x^2+5xy-12y^2, what do yo mean by a prime?

Answer 16

how do i solve this one? isnt 5 prime?

Answer 17

ok
make 5 = 5 *1 or 5 = 1*5

Answer 18

2x^2+5xy-12y^2 = (x+4y) (2x-3y)

Answer 19

that is after some trail and error for the numbers and signs till it fits

Answer 20

i came up with (2x^2+5)(xy-6y^2) as the solution is that correct

Answer 21

you have to factor the x^2 --- > x*x and the y^2 --->y*y

Answer 22

oooooo ok

Answer 23

so when we have here with this little more difficult than the situation before, like what we have 2X^2 , just make 2x*x , wher the 12 y^2 could be many choices ( 4y*3y or 3y*4y , then 2y*6y ot 6y*2y)

Answer 24

the secret key is that :

Answer 25

First step : factor the first squared term into two factors of 1st degree

Answer 26

Second Step: go to the third term and alsoo factor it into 2 multi[liers

Answer 27

but in step 2 take care , you have to get 2 multipliers that meet the condition of when doing algebracilly sum , the sum or subtract to equal = the middle term with the exact sign

Answer 28

hope with more practise , no problem you will find, but try to get the skill without any rush

Answer 29

let the motive inside you mobalize your work. don't give up, it's easy, and with some patcience, things get easier.

Answer 30

http://www.purplemath.com/modules/solvquad.htm
I found this in one of the thread being asked to help.

Answer 31

thank you!!