Ask your own question, for FREE!
Mathematics 15 Online
OpenStudy (gg):

How to find number of zeros of complex polynomial in some area?

OpenStudy (anonymous):

umm if you can post a problem, I might be able to help you.

OpenStudy (gg):

ok, wait a second. thanks :)

OpenStudy (gg):

how many zeros polynomial P(z)= 3z^6 +z^5+ z^4+ 2z^3 + 10z^2+ z+1 has in area 1<|z|<2

OpenStudy (anonymous):

potential zeros are \[\pm1,1/3\]

OpenStudy (anonymous):

oh, since the signs does not change anywhere, I think there are no real solutions

OpenStudy (anonymous):

Yup, but what about Complex...

OpenStudy (anonymous):

all 6 roots are complex

OpenStudy (anonymous):

There are complex solutions of course http://www.wolframalpha.com/input/?i=3z^6+%2Bz^5%2B+z^4%2B+2z^3+%2B+10z^2%2B+z%2B1

OpenStudy (gg):

thanks, but I need to know HOW to find zeros in that area

OpenStudy (gg):

I can't use wolfram on exam :D

OpenStudy (anonymous):

Me too...

OpenStudy (anonymous):

1<|z|<2 represent range of real number(I believe) but there are no real roots

OpenStudy (anonymous):

I know you can't :) I did this kinds stuff over 2 decades ago and haven't touched it since - and don't remember much of it.

OpenStudy (anonymous):

Imran, why does 1<|z|<=2 represent real numbers ?

OpenStudy (anonymous):

nvm, I didn't read the question, they meant on complex plane

OpenStudy (anonymous):

\[|1+i|=\sqrt{2}\]

OpenStudy (anonymous):

Gg - any clues you can give us from notes you took in class ? :)

OpenStudy (anonymous):

You can try the factors of the last term divided by the factors of the first term. That's how imranmeah probably got the ±1, ±1/3, and then try synthetic division to see if any of them work...

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!