Question

find limit then use l'hopital's rule to check it.

lim of x approaches 2 for

f(x)=[(x^2)-4]/[(x^2)+2x-8]

Answer 1

answer is 2/3? says the book

Answer 2

it's clear that when we subtitute dierctly by x=2 it will be undtermiend form , so using l'hopital rule ===> lim (2x/(2x-2) = 4/(4-2) =4/2 =2

Answer 3

sorry it's lim (2x/(2x-2) = 4/(4+2) =4/6 =2/3

Answer 4

I missed the positive sign before

Answer 5

so just find the deravative of the numerator / derivative of denomerator , then subtitute for x=2 , you get the value

Answer 6

hey thank you raheen, you've been such a great help. :)

Answer 7

you are welcom, any time.