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Mathematics
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OpenStudy (anonymous):
who wanna help me
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OpenStudy (anonymous):
I have a lot of free time
OpenStudy (amistre64):
your online behaviour is bordering on getting you a limited suspension. Just a to let you know ....
OpenStudy (anonymous):
ummmmm wat do u mean by that cause you dont have to help me
OpenStudy (anonymous):
There is some enforced (but not explicitly stated) policy about not deleting questions after you get help with them. So I suggest you stop doing that.
OpenStudy (amistre64):
i mean that you are being rude to those that are willing to help you by deleting your questions instead of interacting within them
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OpenStudy (anonymous):
ok wel srry
OpenStudy (amistre64):
'sok :) just wanting you to be aware it
OpenStudy (anonymous):
2x+3=7
OpenStudy (anonymous):
solve for x
OpenStudy (anonymous):
4=x
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OpenStudy (anonymous):
rite
OpenStudy (anonymous):
Not quite. If you subtract 3 from both sides you have:
2x = 4
So if 2 times x is 4 what must x be?
OpenStudy (anonymous):
8
OpenStudy (anonymous):
No. 4 is twice x.
OpenStudy (anonymous):
\[2x = 4\]
Divide both sides by 2.
\[\frac{\cancel{2}x}{\cancel{2}} = \frac{4}{2}\]
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