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Mathematics 15 Online
OpenStudy (anonymous):

who wanna help me

OpenStudy (anonymous):

I have a lot of free time

OpenStudy (amistre64):

your online behaviour is bordering on getting you a limited suspension. Just a to let you know ....

OpenStudy (anonymous):

ummmmm wat do u mean by that cause you dont have to help me

OpenStudy (anonymous):

There is some enforced (but not explicitly stated) policy about not deleting questions after you get help with them. So I suggest you stop doing that.

OpenStudy (amistre64):

i mean that you are being rude to those that are willing to help you by deleting your questions instead of interacting within them

OpenStudy (anonymous):

ok wel srry

OpenStudy (amistre64):

'sok :) just wanting you to be aware it

OpenStudy (anonymous):

2x+3=7

OpenStudy (anonymous):

solve for x

OpenStudy (anonymous):

4=x

OpenStudy (anonymous):

rite

OpenStudy (anonymous):

Not quite. If you subtract 3 from both sides you have: 2x = 4 So if 2 times x is 4 what must x be?

OpenStudy (anonymous):

8

OpenStudy (anonymous):

No. 4 is twice x.

OpenStudy (anonymous):

\[2x = 4\] Divide both sides by 2. \[\frac{\cancel{2}x}{\cancel{2}} = \frac{4}{2}\]

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