Question

need help using scientific and engineering notation.
these are the problems i'm working on:
1.2 x 10e4 = ? x 10e3
0.5 x 10e-4 = ? x 10e-6
125.0 x 10e5 = ? x 10e6
250 x 10e-5 = ? x 10e-4

Answer 1

"e" in this light i believe means "exponent"?

Answer 2

yeah i'm dealing with powers of ten

Answer 3

1234 (10^2) = 123400 , which tells me the decimal moves right when we increase the exponent. and by default, moves left when it decreases

Answer 4

\[10^{4}=1000\]\[1.2\times10^{4}=1200\]\[10^{3}=100\]\[1200=100\times?\]It really helps to visualize what they are in expanded form.

Answer 5

1.2 x 10e4 = ? x 10e3 ; the exponent decreased by 1, so lets move the deci left by 1

1.2 x 10e4 = .12 x 10e3 id say

Answer 6

Bah 1200 should be 12000

Answer 7

0.5 x 10e-4 = ? x 10e-6 is moved 2 to the left

0.5 x 10e-4 = .005 x 10e-6 perhaps?

Answer 8

ok so 1.2 times 10^4 would be 0.12 times 10^3?

Answer 9

looks good to me

Answer 10

... but id have to dbl chk myself to make sure ....

Answer 11

so to convert them i just have to figure out where to move the decimal point?

Answer 12

yes

Answer 13

and the movement of the exponent is the clue

Answer 14

1.00 * 10^0 = 1.00
1.00 * 10^1 = 10.0
1.00 * 10^2 = 100.

Answer 15

so 0.5 times 10^-4 would be .005 times 10^-6?

Answer 16

im sure it is, but let me do one more check to clear the cobwebs ..

1.00 * 10^1 = ? * 10^2

10 = ? * 100

10 = .1 * 100 ;

sooo.....

1.00 * 10^1 = .1 * 10^2

yep, i had it backwards ...

Answer 17

0.5 times 10^-4 = 50. times 10^-6 then

Answer 18

ok thanks.

Answer 19

when in doubt, just work it out with what you can remember till you recall what needs to be done :) good luck with it