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OpenStudy (anonymous):
Inverse of 1+x/(2+x)?
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OpenStudy (anonymous):
y = 1 + x/(2+x)
y(2+x) = 2 + x + x
2y + xy = 2 + 2x
xy - 2x = 2 - 2y
x (y-2) = 2 - 2y
x = 2(1-y) / (y-2)
inverse =
f-1(x) = 2(1-x) / (x-2)
OpenStudy (anonymous):
the answer sheet says the denominantor is 1-x
OpenStudy (anonymous):
hmm - cant see whats wrong with my algebra
OpenStudy (anonymous):
x=1+y/2+y
x(2+y)=1+y
2x+xy=1+y
xy-y=-2x+1
y(x-1)=-2x+1
y=-2x+1/x-1
OpenStudy (anonymous):
you had one to many x's in your second step
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OpenStudy (anonymous):
aaaand the numerator isnt -2x on the answer sheet
OpenStudy (anonymous):
hmmm, now Im a little confused. lol
OpenStudy (anonymous):
oh i see whats happened - i assumed that original expression was 1 + (x / 2+x) - it would avoid confusion if you had typed it as (1+x)/ (2 + x)
OpenStudy (anonymous):
the answer is 2x-1/1-x...
OpenStudy (anonymous):
oooh sorry
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OpenStudy (anonymous):
Ahh ok so they factored out a negative so it should look like this
2x-1/-x+1
OpenStudy (anonymous):
or the way you wrote they are equal
OpenStudy (anonymous):
yup
OpenStudy (anonymous):
gotchya
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