Question

Stumped on a question..
(-1/x )+( 2/x^2+1 )+ ( 1/x^3+x )
Thank you! :)

Answer 1

least common multiple of the denominators is
\[x^3+x\] so multiply first one top and bottom by
\[x^2+1\] and the second one top and bottom by x and third one leave alone. then add in the numerator

Answer 2

\[\frac{-1}{x}\frac{(x^2+1)}{(x^2+1)}+\frac{2}{(x^2+1)}\frac{x}{x}+\frac{1}{x^3+x}\]

Answer 3

get
\[\frac{-x^2-1+2x+1}{x^3+x}\]
\[=\frac{-x^2+2x}{x^3+x}\]
\[=\frac{x(2-x)}{x(x^2+1)}\]
\[=\frac{2-x}{x^2+1}\]

Answer 4

Oh woah, the way you explained the question made it so simple. Thanks a lot!