If a construction worker drops a wrench from the top of a building 375 feet high the wrench will be s(t) = −16t2 + 375 feet above the ground after t seconds. Determine the velocity of the wrench 4 seonds after it was was dropped. Answer in units of ft/sec
do you know about derivatives?
yes
to find velocity at a given moment, also known as instantaneous velocity, we need to know how to take the derivative of an equation; good
whats the derivative that you come up with here?
well you can take the derivative of s(t)=62t^2+ 375 by first moving the 2 in front of 162 and multiply both which well give you 324t and 375 will turn to 0
got a few typos in that, but yes, the premise is good
-16t^2 results in -32t so our velocity at t=4 is -32(4) = -128
ft per second
oh ok, thanks again!
-128 ft/sect
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