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what is the inverse of this : f(x)=(2x-x^3)^5
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15
f(x)=(2x-x^3)^5 Inverse will be: 1/((2x-x^3)^5) http://www.wolframalpha.com/input/?i=1%2F%28%282x-x^3%29^5%29
Have you tried taking the derivative, inversing, and multiplying by -1?
i cant solve it
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This requires solving a cubic to do... you sure the question is to find the inverse function of \[f(x)=(2x-x^3)^5\]?
yes. im sure. it is stated in the book.
f(x) is not bijective function. Inverse function does not exist. example \[f(0)=f(\pm\sqrt{2})=0\]
Well spotted nikvist!
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