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Physics 21 Online
OpenStudy (anonymous):

A particles position is given by x=15.0-18.00t+3t2, in which x is in meters ant t is in seconds. where is the particle when it momentarily stops

OpenStudy (anonymous):

So, i think I'm supposed to take the derivative? does anyone know?

OpenStudy (anonymous):

Yes, take one derivative. That will give you the equation for velocity, which if made equal to 0 (momentarily stops), then solve for t (time). Plug that time back in equation for displacement and obtain X(t).

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