Question

what is the cubed root of -1

Answer 1

\[x^3 + 1 = 0 \]
\[(x + 1 )(x^2 + 1 - x)=0\]

Answer 2

\(x= - 1\) is one of the roots and also the only real root...

Answer 3

For the complex part we need to use quadratic formula.

Answer 4

\[\sqrt[3]{-1}=-1^(1/3) = -1\]

Answer 5

\[x^2+ 1 -x = 0\]
\[x = \frac{1 \pm i\sqrt3}{2}\]

Answer 6

Now you have three roots \( -1 , \frac{1 + i\sqrt3}{2} , \frac{1 - i\sqrt3}{2}\)