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OpenStudy (anonymous):
post it
OpenStudy (anonymous):
err you need help but you want us to help or not?
OpenStudy (anonymous):
OpenStudy (anonymous):
my server was out for little bit, sorry!
OpenStudy (anonymous):
:D this site is really harms the machine -.-'
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OpenStudy (anonymous):
that for sure, lol
OpenStudy (anonymous):
it looks like differential o.O
OpenStudy (anonymous):
yep!
OpenStudy (anonymous):
i cant bring up your diagram for some reason
OpenStudy (anonymous):
what version of windows do you have?
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OpenStudy (anonymous):
ta just put your screen shot to paint and save it as .jpg file then there won't be any problem
OpenStudy (anonymous):
OpenStudy (anonymous):
OpenStudy (anonymous):
this is a lot easier than it looks at first glance, especially if you know how to take derivatives quickly. do you?
OpenStudy (anonymous):
yes!
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OpenStudy (anonymous):
good then the derivaitive from the left is -1 and the derivative from the right is
\[\frac{1}{(7-x)^2}\]
OpenStudy (anonymous):
clear what i did right? for the left i used
\[f(x)=7-x\] and from the right i used
\[f(x)=\frac{1}{7-x}\]
OpenStudy (anonymous):
to get the two derivatives. then replace x by 6
derivative from the left is a constant. it is -1
when you replace x by 6 in the second expression you get 1
OpenStudy (anonymous):
yes!
OpenStudy (anonymous):
it only looked hard
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OpenStudy (anonymous):
ok, so does f' (6) exists, if does how would you find its values
OpenStudy (anonymous):
clearly not since
\[1\neq -1\]
OpenStudy (anonymous):
oh ok, so if they both had the same solution then, they would exists
OpenStudy (anonymous):
true?
OpenStudy (anonymous):
oh yes sorry. if the limits are the same then it exists and if not then no