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Mathematics 22 Online
OpenStudy (anonymous):

need help with problem

OpenStudy (anonymous):

post it

OpenStudy (anonymous):

err you need help but you want us to help or not?

OpenStudy (anonymous):

OpenStudy (anonymous):

my server was out for little bit, sorry!

OpenStudy (anonymous):

:D this site is really harms the machine -.-'

OpenStudy (anonymous):

that for sure, lol

OpenStudy (anonymous):

it looks like differential o.O

OpenStudy (anonymous):

yep!

OpenStudy (anonymous):

i cant bring up your diagram for some reason

OpenStudy (anonymous):

what version of windows do you have?

OpenStudy (anonymous):

ta just put your screen shot to paint and save it as .jpg file then there won't be any problem

OpenStudy (anonymous):

OpenStudy (anonymous):

OpenStudy (anonymous):

this is a lot easier than it looks at first glance, especially if you know how to take derivatives quickly. do you?

OpenStudy (anonymous):

yes!

OpenStudy (anonymous):

good then the derivaitive from the left is -1 and the derivative from the right is \[\frac{1}{(7-x)^2}\]

OpenStudy (anonymous):

clear what i did right? for the left i used \[f(x)=7-x\] and from the right i used \[f(x)=\frac{1}{7-x}\]

OpenStudy (anonymous):

to get the two derivatives. then replace x by 6 derivative from the left is a constant. it is -1 when you replace x by 6 in the second expression you get 1

OpenStudy (anonymous):

yes!

OpenStudy (anonymous):

it only looked hard

OpenStudy (anonymous):

ok, so does f' (6) exists, if does how would you find its values

OpenStudy (anonymous):

clearly not since \[1\neq -1\]

OpenStudy (anonymous):

oh ok, so if they both had the same solution then, they would exists

OpenStudy (anonymous):

true?

OpenStudy (anonymous):

oh yes sorry. if the limits are the same then it exists and if not then no

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