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Mathematics 22 Online
OpenStudy (anonymous):

evaluate the indefinite integrals

OpenStudy (anonymous):

\[\int\limits x \sin(x ^{2}) dx\]

OpenStudy (anonymous):

take u = (x^2) ; therefore du = 2xdx tell me if you'd like me to continue :)

OpenStudy (anonymous):

ok i got that steps but whats the integral of sin? cos?

OpenStudy (anonymous):

-cos

OpenStudy (anonymous):

derivative of sin is +cos

OpenStudy (anonymous):

o darn wait can you explain please

OpenStudy (anonymous):

well, there are proofs that go with it, that are very long on keyboard. but integral is basically the inverse of deriving. deriviative of sin(x) is cos(x)dx, therefore the integral of cos(x)dx is sin(x). the derivative of cos(x) = -sin(x)dx, therefore the integral of sin(x) = -cos(x)dx

OpenStudy (anonymous):

ok cool thanks now i know where im going thanks

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