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evaluate the indefinite integrals
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\[\int\limits x \sin(x ^{2}) dx\]
take u = (x^2) ; therefore du = 2xdx tell me if you'd like me to continue :)
ok i got that steps but whats the integral of sin? cos?
-cos
derivative of sin is +cos
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o darn wait can you explain please
well, there are proofs that go with it, that are very long on keyboard. but integral is basically the inverse of deriving. deriviative of sin(x) is cos(x)dx, therefore the integral of cos(x)dx is sin(x). the derivative of cos(x) = -sin(x)dx, therefore the integral of sin(x) = -cos(x)dx
ok cool thanks now i know where im going thanks
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