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1/4log3 81+ 1/2log3 9- log3 27
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\[\frac{1}{4}\log_3(81)=\log_3(\sqrt[4]{81})=\log_3(3)=1\]
similarly \[\frac{1}{2}\log_3(9)=\log_3(\sqrt{9})=\log_3(3)=1\]
and finally \[\log_3(27)=\log_3(3^3)=3\]
so "final answer" is \[1+1-3=-1\]
wow thank you so much!!
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