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Mathematics 15 Online
OpenStudy (anonymous):

find f'(x) f(x)=sqrt X using f(x+h)-f(x) / h

OpenStudy (amistre64):

conjugates is the key

OpenStudy (amistre64):

\[\frac{f(x+h)-f(x)}{h}*\frac{f(x+h)+f(x)}{f(x+h)+f(x)}\] \[\frac{(x+h)-(x)}{h(f(x+h)+f(x))}\] \[\frac{h}{h(f(x+h)+f(x))}\] \[\frac{1}{f(x+h)+f(x)}\]

OpenStudy (amistre64):

and when h=0 by the limit we get: \[\frac{1}{2f(x)}\]

OpenStudy (amistre64):

the only reason that works for the top like that is cause f(x) = sqrt(x), its not that nice when its other things tho

OpenStudy (anonymous):

ah i see

OpenStudy (anonymous):

thanks

OpenStudy (amistre64):

youre welcome

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