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find f'(x) f(x)=sqrt X using f(x+h)-f(x) / h
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conjugates is the key
\[\frac{f(x+h)-f(x)}{h}*\frac{f(x+h)+f(x)}{f(x+h)+f(x)}\] \[\frac{(x+h)-(x)}{h(f(x+h)+f(x))}\] \[\frac{h}{h(f(x+h)+f(x))}\] \[\frac{1}{f(x+h)+f(x)}\]
and when h=0 by the limit we get: \[\frac{1}{2f(x)}\]
the only reason that works for the top like that is cause f(x) = sqrt(x), its not that nice when its other things tho
ah i see
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thanks
youre welcome
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